SATHEE: Rotational Motion Question 127

Rotational Motion Question 127

Question: A hoop rolls on a horizontal ground without Slipping with linear speed $v$ . Speed of a particle $P$ on the circumference of the hoop at angle $θ$ is

Options:

A) $2 v \sin (θ / 2)$

B) $v \sin θ$

C) $2 v \cos (θ / 2)$

D) $v \cos θ$

Show Answer

Answer:

Correct Answer: A

Solution:

[a]

$v_{p} = \sqrt{v^{2} + v^{2} + 2 v v \cos (180 - θ)}$

$\Rightarrow v_{p} = \sqrt{2 v^{2} 1 - c o s θ}$

$= 2 v \sin (θ / 2)$

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Rotational Motion Question 127

Question: A hoop rolls on a horizontal ground without Slipping with linear speed v . Speed of a particle P on the circumference of the hoop at angle θ is

Options:

Answer:

Solution:

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Question: A hoop rolls on a horizontal ground without Slipping with linear speed $v$ . Speed of a particle $P$ on the circumference of the hoop at angle $θ$ is