Rotational Motion Question 127

Question: A hoop rolls on a horizontal ground without Slipping with linear speed $v$ . Speed of a particle $P$ on the circumference of the hoop at angle $\theta $ is

Options:

A) $2v\sin (\theta /2)$

B) $v\sin \theta $

C) $2v\cos (\theta /2)$

D) $v\cos \theta $

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Answer:

Correct Answer: A

Solution:

[a]

$v _{p}=\sqrt{v^{2}+v^{2}+2vv\cos (180-\theta )}$

$\Rightarrow v _{p}=\sqrt {2v^{2}1-cos\theta }$

$=2v\sin (\theta /2)$



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