SATHEE: Rotational Motion Question 118

Rotational Motion Question 118

Question: A ball collides with a fixed inclined plane of inclination $θ$ after falling through a distance $h$ ? If it moves horizontally just after the impact, the coefficient of restitution is

Options:

A) $\tan θ$

B) $\tan^{2} θ$

C) $\cot^{} θ$

D) $\cot^{2} θ$

Show Answer

Answer:

Correct Answer: B

Solution:

[b]Writing coefficient of restitution equation

$e = \frac{v_{2} - v_{1}}{u_{1} - u_{2}} = \frac{0 - v \sin θ}{- v_{0} \cos θ - 0} = \frac{v}{v_{0}} \tan θ$

The velocity of ball will remain unchanged in the direction of sloping surface (common tangent)

$\Rightarrow v_{0} \sin θ = v \cos θ$

$\Rightarrow \frac{v}{v_{0}} = \tan θ$

$\Rightarrow e = \tan^{2} θ .$

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Rotational Motion Question 118

Question: A ball collides with a fixed inclined plane of inclination θ after falling through a distanceh ? If it moves horizontally just after the impact, the coefficient of restitution is

Options:

Answer:

Solution:

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Question: A ball collides with a fixed inclined plane of inclination $θ$ after falling through a distance $h$ ? If it moves horizontally just after the impact, the coefficient of restitution is