SATHEE: Rotational Motion Question 115

Rotational Motion Question 115

Question: Three blocks are initially placed . Block $A$ has mass m and initial velocity $v$ to the right. Block $B$ with mass and block C with mass $4 m$ are both initially at rest. Neglect friction. All collisions are elastic. The final velocity of blocks $A$ is

Options:

A) 0.6 $v$ to the left

B) 1.4 $v$ to the left

C) $v$ to the left

D) 0.4 $v$ to the right

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Answer:

Correct Answer: A

Solution:

[a] Since, $A$ and 5 have same mass.

So, after elastic collision, they interchange their velocity.

$∴ v_{B} = v$

After collision between $B$ and $C$ , $v_{B}^{'} = (\frac{m - 4 m}{m + 4 m}) v + (\frac{2 \times 4 m \times 0}{m + 4 m}) = - \frac{3}{5} v$

Again, collision takes place between $A$ and $B$ .

So, velocity will be interchanged.

$∴ v_{A}^{'} = (v_{B}^{'}) = \frac{3}{5} v$ toward left

Rotational Motion Question 115

Question: Three blocks are initially placed . Block $A$ has mass m and initial velocity $v$ to the right. Block $B$ with mass and block C with mass $4 m$ are both initially at rest. Neglect friction. All collisions are elastic. The final velocity of blocks $A$ is

Options:

Answer:

Solution:

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Rotational Motion Question 115

Question: Three blocks are initially placed . Block A has mass m and initial velocity v to the right. Block B with mass and block C with mass 4m are both initially at rest. Neglect friction. All collisions are elastic. The final velocity of blocks A is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Three blocks are initially placed . Block $A$ has mass m and initial velocity $v$ to the right. Block $B$ with mass and block C with mass $4 m$ are both initially at rest. Neglect friction. All collisions are elastic. The final velocity of blocks $A$ is