Rotational Motion Question 111

Question: An object of mass 3m splits into three equal fragments. Two fragments have velocities vj^ and vi^ . The velocity of the third fragment is

Options:

A)v(j^i^)

B) v(i^j^)

C)v(i^+j^)

D) v(i^+j^)2

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Answer:

Correct Answer: C

Solution:

[c] Initial momentum of 3m mass =0 Due to explosion this mass splits into three fragments of equal masses.

Final momentum of system = mV+mvi^+mvj^

(iii) By the law of conservation of linear momentum mV+mvi^+mvj^=0V=v(i^+j^)



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