Rotational Motion Question 108

Question: In a gravity free space, a man of mass M standing at a height h above the floor, throws a ball of mass m straight down with a speed u . When the ball reaches the floor, the distance of the man above the floor will be

Options:

A)h(1+m/M)

B)h(2m/M)

C)2h

D)a function of m , M , h and u

Show Answer

Answer:

Correct Answer: A

Solution:

[a]As in gravity free space displacement of centre of mass of man and ball system should not move.

If displacement of the ball be h then the displacement of man in upward direction.

mh=Mhh=mhM

(i) Hence the position of man from ground H=h+h=h=h1+mM



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