Rotational Motion Question 102

Question: A bag (mass M ) hangs by a long thread and a bullet (mass m ) comes horizontally with velocity v and gets caught in the bag. Then for the combined (bag + bullet) system

Options:

A) Momentum is mvMM+m

B)Kinetic energy is mv22

C)Momentum is mv(M+m)M

D)Kinetic energy is m2v22(M+m)

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Answer:

Correct Answer: D

Solution:

[d] Initial momentum =mv Final momentum = (m+M)V By conservation of momentum $

mv=(m+M)V

Velocity of (bag +bullet) system V=mvM+m

Kinetic energy =12(m+M)V2 =12(m+M)(mvM+m)2=12m2v2(M+m)



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