Rotational Motion Question 101
Question: A constant torque of $1000 \mathrm{~N} \mathrm{~m}$ turns a wheel of moment of inertia $100 \mathrm{~kg} \mathrm{~m}^2$ about an axis passing through its centre. Starting from rest, its angular velocity after $3s \mathrm{}$ is :-
Options:
A)1 rads$^{−1}$
B)5 rads$^{−1}$
C)10 rads$^{−1}$
D)15 rads$^{−1}$
Show Answer
Answer:
Correct Answer: D
Solution:
We know that ${T=Iα1000=200×α⇒α=5rad/s^{2}}$ .
Now we know ${ω=ωo+αt}$, and ${ωo=0ω=5×3=15}$ rads$^{−1}$
