Properties Of Solids And Liquids Question 86
Question: 10 gm of ice at 0°C is mixed with 100 gm of water at 50°C. What is the resultant temperature of mixture [AFMC 2005]
Options:
A) 31.2°C
B) 32.8°C
C) 36.7°C
D) 38.2°C
Show Answer
Answer:
Correct Answer: D
Solution:
$ {\theta _{\text{mix}}}=\frac{m _{W}{\theta _{W}}-\frac{{m _{i}}{L _{i}}}{c _{W}}}{{m _{i}}+m _{W}} $
$ =\frac{100\times 50-10\times \frac{80}{1}}{10+100}\approx 38.2{}^\circ C $