Properties Of Solids And Liquids Question 86

Question: 10 gm of ice at 0°C is mixed with 100 gm of water at 50°C. What is the resultant temperature of mixture [AFMC 2005]

Options:

A) 31.2°C

B) 32.8°C

C) 36.7°C

D) 38.2°C

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Answer:

Correct Answer: D

Solution:

$ {\theta _{\text{mix}}}=\frac{m _{W}{\theta _{W}}-\frac{{m _{i}}{L _{i}}}{c _{W}}}{{m _{i}}+m _{W}} $

$ =\frac{100\times 50-10\times \frac{80}{1}}{10+100}\approx 38.2{}^\circ C $



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