SATHEE: Properties Of Solids And Liquids Question 77

Properties Of Solids And Liquids Question 77

Question: The relative humidity on a day, when partial pressure of water vapour is $0.012 \times 10^{5} P a$ at 12°C is (take vapour pressure of water at this temperature as $0.016 \times 10^{5} P a$ ) [AIIMS 1998]

Options:

A) 70%

B) 40%

C) 75%

D) 25%

Show Answer

Answer:

Correct Answer: C

Solution:

Partial pressure of water vapour $P_{W} = 0.012 \times 10^{5} P a$ ,

Vapour pressure of water $P_{V} = 0.016 \times 10^{5} P a$ .

The relative humidity at a given temperature is given by $= \frac{Partial pressure of water vapour}{Vapour pressure of water}$

$= \frac{0.012 \times 10^{5}}{0.016 \times 10^{5}} = 0.75 = 75$

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Properties Of Solids And Liquids Question 77

Question: The relative humidity on a day, when partial pressure of water vapour is 0.012×105Pa at 12°C is (take vapour pressure of water at this temperature as 0.016×105Pa ) [AIIMS 1998]

Options:

Answer:

Solution:

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Question: The relative humidity on a day, when partial pressure of water vapour is $0.012 \times 10^{5} P a$ at 12°C is (take vapour pressure of water at this temperature as $0.016 \times 10^{5} P a$ ) [AIIMS 1998]