Properties Of Solids And Liquids Question 69

Question: How many grams of a liquid of specific heat 0.2 at a temperature 40°C must be mixed with 100 gm of a liquid of specific heat of 0.5 at a temperature 20°C, so that the final temperature of the mixture becomes 32°C [Pb. PET 1999]

Options:

A) 175 gm

B) 300 g

C) 295 gm

D) 375 g

Show Answer

Answer:

Correct Answer: D

Solution:

Temperature of mixture θ=m1c1θ1+m2c2θ2m1c1+m2θ2

therefore 32=m1×0.2×40+100×0.5×20m1×0.2+100×0.5

therefore m1=375gm



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