Properties Of Solids And Liquids Question 586

Question: A lead bullet of 10 g travelling at 300 m/s strikes against a block of wood and comes to rest. Assuming 50% of heat is absorbed by the bullet, the increase in its temperature is (Specific heat of lead = 150J/kg, K)

Options:

A) $ 100{}^\circ C $

B) $ 125{}^\circ C $

C) $ 150{}^\circ C $

D) $ 200{}^\circ C $

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Answer:

Correct Answer: C

Solution:

Since specific heat of lead is given in Joules, hence use $ W=Q $ instead of $ W=JQ $ . $ \Rightarrow $ $ \frac{1}{2}\times ( \frac{1}{2}mv^{2} )=m.c.\Delta \theta $

$ \Rightarrow $ $ \Delta \theta =\frac{v^{2}}{4c}=\frac{{{(300)}^{2}}}{4\times 150}=150{}^\circ C $ .



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