Properties Of Solids And Liquids Question 548

Question: 4 gms of steam at 100C is added to 20 gms of water at 46C in a container of negligible mass. Assuming no heat is lost to surrounding, the mass of water in container at thermal equilibrium is. Latent heat of vaporisation =540cal/gm . Specific heat of water =1cal/gmC .

Options:

A) 18gm

B) 20gm

C) 22gm

D) 24gm

Show Answer

Answer:

Correct Answer: C

Solution:

Heat released by steam inconversion to water at 100C is $ Q _{1}=mL=4x540=2160cal.

$ Heat required to raise temperature of water from is

Q2=mSΔθ =20×1×54=1080J

Q1>Q2andQ1Q2=2

Hence all steam is not converted to water only half steam shall be converted to water

Final mass of water =20+2=22gm



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