Properties Of Solids And Liquids Question 542

Question: A constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at $ 0{}^\circ C $ and $ 100{}^\circ C $ respectively. When the pressure reading is 60 cm of mercury, the temperature is

Options:

A) $ 25{}^\circ C $

B) $ 40{}^\circ C~ $

C) $ 15{}^\circ C $

D) $ {{12.5}^{o}}C $

Show Answer

Answer:

Correct Answer: A

Solution:

$ t=\frac{( P _{1}-P _{0} )}{( P _{100}-P _{0} )}\times 100{}^\circ C $

$ =\frac{( 60-50 )}{( 90-50 )}\times 100=25{}^\circ C $



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