Properties Of Solids And Liquids Question 474

Question: A pendulum clock keeps correct time at 0°C. Its mean coefficient of linear expansions is $ \alpha /{}^\circ C $ , then the loss in seconds per day by the clock if the temperature rises by t°C is [AFMC 1993]

Options:

A) $ \frac{\frac{1}{2}\alpha t\times 864000}{1-\frac{\alpha t}{2}} $

B) $ \frac{1}{2}\alpha t\times 86400 $

C) $ \frac{\frac{1}{2}\alpha t\times 86400}{{{( 1-\frac{\alpha t}{2} )}^{2}}} $

D) $ \frac{\frac{1}{2}\alpha t\times 86400}{1+\frac{\alpha t}{2}} $

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Answer:

Correct Answer: B

Solution:

Loss in time per second $ \frac{\Delta T}{T}=\frac{1}{2}\alpha \Delta \theta =\frac{1}{2}\alpha (t-0) $

therefore loss in time per day $ \Delta t=( \frac{1}{2}\alpha t )t=\frac{1}{2}\alpha t\times (24\times 60\times 60)=\frac{1}{2}\alpha t\times 86400 $



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