Properties Of Solids And Liquids Question 460

Question: A system S receives heat continuously from an electrical heater of power 10 W. The temperature of S becomes constant at 50C when the surrounding temperature is 20C . After the heater is switched off; S cools from 35.1C to 34.9C in 1 minute. The heat capacity of S is

Options:

A) 100J/C

B) 300J/C

C) 750J/C

D) 1500J/C

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Rate of loss of heat difference in tem- perature with the surroundings.

At 50C,dQdt=k(5020)=10 , where k = constant k=l/3

At an angle temperature of 35C , dQdt=13(3520)J/s=5J/s .

Heat lost in 1 minutes =dQdt×60J=5×60J=300J=Q

Fall in temperature =0.2C=AQ . Q=cΔθ.

Heat capacity =c=Qdθ=300J0.2oC=1500J/oC.



NCERT Chapter Video Solution

Dual Pane