SATHEE: Properties Of Solids And Liquids Question 456

Properties Of Solids And Liquids Question 456

Question: Consider two hot bodies $B_{1}$ and $B_{2}$ which have temperatures $109^{\circ} C$ and $89^{\circ} C$ respectively at t=0. The temperature of the surroundings is $49^{\circ} C$ . The ratio of the respective rates of cooling $R_{1}$ and $R_{2}$ of these two bodies at t = 0 will be

Options:

A) $R_{1} : R_{2} = 3 : 2$

B) $R_{1} : R_{2} = 5 : 4$

C) $R_{1} : R_{2} = 2 : 3$

D) $R_{1} : R_{2} = 4 : 5$

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Answer:

Correct Answer: A

Solution:

[a] Initially at t=0 Rate of cooling (R) $\propto$ Fall in temperature of body $\Rightarrow \frac{R_{1}}{R_{2}} = \frac{θ_{1} - θ_{0}}{θ_{2} - θ_{0}} = \frac{100 - 40}{80 - 40} = \frac{3}{2}$

Properties Of Solids And Liquids Question 456

Question: Consider two hot bodies $B_{1}$ and $B_{2}$ which have temperatures $109^{\circ} C$ and $89^{\circ} C$ respectively at t=0. The temperature of the surroundings is $49^{\circ} C$ . The ratio of the respective rates of cooling $R_{1}$ and $R_{2}$ of these two bodies at t = 0 will be

Options:

Answer:

Solution:

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Properties Of Solids And Liquids Question 456

Question: Consider two hot bodies B1 and B2 which have temperatures 109∘C and 89∘C respectively at t=0. The temperature of the surroundings is49∘C . The ratio of the respective rates of cooling R1 and R2 of these two bodies at t = 0 will be

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Consider two hot bodies $B_{1}$ and $B_{2}$ which have temperatures $109^{\circ} C$ and $89^{\circ} C$ respectively at t=0. The temperature of the surroundings is $49^{\circ} C$ . The ratio of the respective rates of cooling $R_{1}$ and $R_{2}$ of these two bodies at t = 0 will be