SATHEE: Properties Of Solids And Liquids Question 451

Properties Of Solids And Liquids Question 451

Question: The room heater can maintain only $16^{\circ} C$ in the room when the temperature outside is $- 20^{\circ} C$ . It is not warm and comfortable, that is why the electric stove with power of 1 kW is also plugged in. Together these two devices maintain the room temperature of $22^{\circ} C$ . Determine the thermal power of the heater.

Options:

A) 3 kW

B) 4 kW

C) 5 kW

D) 6 kW

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Rate of heat loss with only room heater $P h = \frac{Δ Q}{Δ t} = C (16 + 20), C = c o n s t a n t$ while for both heater and stove it is $p_{h} + p_{s} = {(\frac{Δ Q}{Δ t})}^{^{'}} = C (22 + 20)$

$\frac{p_{h}}{p_{h} + p_{s}} = \frac{36}{42} \Rightarrow 7 p_{h} = 6 p_{h} + 6 p_{s}$

$\Rightarrow p_{h} = 6 p_{s} = 6 k W$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Properties Of Solids And Liquids Question 451

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu