Properties Of Solids And Liquids Question 45

Question: A bullet moving with a uniform velocity v, stops suddenly after hitting the target and the whole mass melts be m, specific heat S, initial temperature 25°C, melting point 475°C and the latent heat L. Then v is given by [NCERT 1972]

Options:

A) mL=mS(47525)+12mv2J

B) mS(47525)+mL=mv22J

C) mS(47525)+mL=mv2J

D) mS(47525)mL=mv22J

Show Answer

Answer:

Correct Answer: B

Solution:

Firstly the temperature of bullet rises up to melting point, then it melts.

Hence according to W=JH .

therefore 12mv2=J.[m.c.Δθ+mL]=J[mS(47525)+mL]

therefore mS(47525)+mL=mv22J



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