Properties Of Solids And Liquids Question 439

Question: A metal ball of surface area 200 square cm, temperature 527C is surrounded by a vessel at27C . If the emissivity of the metal is 0.4, then the rate of loss of heat from the ball is approximately [σ=5.67×108Joulem2×sec×K2]

Options:

A) 108 joule

B) 168 joule

C) 182 joule

D) 192 joule

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Answer:

Correct Answer: C

Solution:

[c] According to Stefan’s Law, the rate of loss of heat is Qt=σA(T14T24)×e

here σ=5.67×108/m2×sec.K2,

T1=527+273=800K,

T2=27+273=300K&A=200×l04m2

So. Qt=5.67×108×2×l02

[(800)4(300)4]×0.4

182joule



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