Properties Of Solids And Liquids Question 430

Question: In an energy recycling process, $ 100g $ of steam at $ 100{}^\circ C $ becomes water at $ 100{}^\circ C $ which converts y g of ice at $ 0{}^\circ C $ into water at $ 100{}^\circ C $ . The numeric value of y is

Options:

A) 100

B) 200

C) 300

D) 400

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Answer:

Correct Answer: C

Solution:

[c] Specific heat of water = 4200 J/kg-K .

Latent heat of fusion $ =3.36\times 10^{5} J/kg $ .

Latent heat of vapourisation $ =22.68\times l0^{5} J/kg $

$ x\times 1{{0}^{-3}}\times 22.68\times 10^{5}J $

$ =y\times 1{{0}^{-3}}\times 3.36\times 10^{5} J+y\times 1{{0}^{-3}}\times 4200\times 100 $

$ \therefore \frac{x}{y}=\frac{7.56}{22.68}=\frac{1}{3} $



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