SATHEE: Properties Of Solids And Liquids Question 394

Properties Of Solids And Liquids Question 394

Question: The temperature of the two outer surfaces of a composite slab, consisting of two materials having coefficients of thermal conductivity K and 2K and thickness x and 4x, respectively, are $T_{2}$ and $T_{1}$

$(T_{2} > T_{1})$ . The rate of heat transfer through the slab, in a steady state is $(\frac{A (T_{2} > T_{1}) K}{x}) f$ , with f equal to

Options:

A) $\frac{2}{3}$

B) $\frac{1}{2}$

C) 1

D) $\frac{1}{3}$

Show Answer

Answer:

Correct Answer: D

Solution:

[d] the thermal resistance is given by $\frac{x}{K A} + \frac{4 x}{2 K A} = \frac{x}{K A} + \frac{2 x}{K A} = \frac{3 x}{K A}$

$∴ \frac{d Q}{d t} = \frac{Δ T}{\frac{3 x}{K A}} = \frac{(T_{2} - T_{1}) K A}{3 x}$

$= \frac{1}{3} \frac{A (T_{2} - T_{1}) K}{x} ∴ f = \frac{1}{3}$

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Properties Of Solids And Liquids Question 394

Question: The temperature of the two outer surfaces of a composite slab, consisting of two materials having coefficients of thermal conductivity K and 2K and thickness x and 4x, respectively, areT2 and T1

Options:

Answer:

Solution:

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Question: The temperature of the two outer surfaces of a composite slab, consisting of two materials having coefficients of thermal conductivity K and 2K and thickness x and 4x, respectively, are $T_{2}$ and $T_{1}$