Properties Of Solids And Liquids Question 394

Question: The temperature of the two outer surfaces of a composite slab, consisting of two materials having coefficients of thermal conductivity K and 2K and thickness x and 4x, respectively, are$ {{T} _{2}} $ and $ T _{1} $

$ ({{T} _{2}}>T _{1}) $ . The rate of heat transfer through the slab, in a steady state is $ ( \frac{A( {{T} _{2}}>T _{1} )K}{x} )f $ , with f equal to

Options:

A) $ \frac{2}{3} $

B) $ \frac{1}{2} $

C) 1

D) $ \frac{1}{3} $

Show Answer

Answer:

Correct Answer: D

Solution:

[d] the thermal resistance is given by $ \frac{x}{KA}+\frac{4x}{2KA}=\frac{x}{KA}+\frac{2x}{KA}=\frac{3x}{KA} $

$ \therefore \frac{dQ}{dt}=\frac{\Delta T}{\frac{3x}{KA}}=\frac{( T _{2}-T _{1} )KA}{3x} $

$ =\frac{1}{3}{ \frac{A( T _{2}-T _{1} )K}{x} }\therefore f=\frac{1}{3} $



NCERT Chapter Video Solution

Dual Pane