Properties Of Solids And Liquids Question 393

Question: 500 g of water and 100 g of ice at $ 0{}^\circ C $ are in a calorimeter whose water equivalent is 40 g. 10 g of steam at $ 100{}^\circ C $ is added to it. Then water in the calorimeter is : (Latent heat of ice =80 cal/g, Latent heat of steam =540 cal/ g)

Options:

A) 580 g

B) 590 g

C) 600 g

D) 610 g

Show Answer

Answer:

Correct Answer: B

Solution:

[b] As Ig of steam at $ 100{}^\circ C $ melts 8g of ice at 10 g of steam will melt $ 8\times 10g $ of ice at $ 0{}^\circ C $ Water in calorimeter =500 + 80+10g=590g



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