Properties Of Solids And Liquids Question 356

Question: 8 mercury drops coalesce to form one mercury drop, the energy changes by a factor of [DCE 2000]

Options:

A) 1

B) 2

C) 4

D) 6

Show Answer

Answer:

Correct Answer: C

Solution:

As volume remains constant therefore R=n1/3r

Energy of big dropEnergy of small drop=4πR2T4πr2T=R2r2

=(8)2/3=4



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