Properties Of Solids And Liquids Question 343

Question: A mercury drop of 1 cm radius is broken into 106 small drops. The energy used will be (surface tension of mercury is 35×10−3N/cm) [Roorkee 1984]

Options:

A) 4.4×10−3J

B)2.2×10−4J

C) 8.8×10−4J

D)104J

Show Answer

Answer:

Correct Answer: A

Solution:

E=4πR2T(n1/3−1)

=4×3.14×10−4×35×10−1(106/3−1)

=4.4×10−3J

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