Properties Of Solids And Liquids Question 323

Question: The pressure inside a small air bubble of radius 0.1 mm situated just below the surface of water will be equal to [Take surface tension of water 70×103Nm1 and atmospheric pressure = 1.013×105Nm2 ] [AMU (Med.) 2002]

Options:

A) 2.054×103Pa

B)1.027×103Pa

C) 1.027×105Pa

D)2.054×105Pa

Show Answer

Answer:

Correct Answer: C

Solution:

Excess pressure inside the air bubble =2Tr

PinPout=2Tr=2×70×1030.1×103=1400Pa

therefore Pin=1400+1.013×105

=0.014×105+1.013×105=1.027×105Pa



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