SATHEE: Properties Of Solids And Liquids Question 284

Properties Of Solids And Liquids Question 284

Question: The height of a mercury barometer is 75 cm at sea level and 50 cm at the top of a hill. Ratio of density of mercury to that of air is 104. The height of the hill is

Options:

A)250 m

B)2.5 km

C)1.25 km

D)750 m

Show Answer

Answer:

Correct Answer: B

Solution:

Difference of pressure between sea level and the top of hill DP $= (h_{1} - h_{2}) \times ρ_{H g} \times g$

$= (75 - 50) \times 10^{- 2} \times ρ_{H g} \times g$ -(i)

and pressure difference due to h meter of airDP = $h \times ρ_{a i r} \times g$ -(ii)

By equating (i) and (ii) we get $h \times ρ_{a i r} \times g = (75 - 50) \times 10^{- 2} \times ρ_{H g} \times g$

$∴ h = 25 \times 10^{- 2} (\frac{ρ_{H g}}{ρ_{a i r}})$

$= 25 \times 10^{- 2} \times 10^{4} = 2500 m$

Height of the hill = 2.5 km.

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Properties Of Solids And Liquids Question 284

Question: The height of a mercury barometer is 75 cm at sea level and 50 cm at the top of a hill. Ratio of density of mercury to that of air is 104. The height of the hill is

Options:

Answer:

Solution:

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