Properties Of Solids And Liquids Question 25

Question: Heat required to convert one gram of ice at 0°C into steam at 100°C is (given Lsteam = 536 cal/gm) [Pb. PMT 1990]

Options:

A) 100 calorie

B) 0.01 kilocalorie

C) 716 calorie

D) 1 kilocalorie

Show Answer

Answer:

Correct Answer: C

Solution:

Conversion of ice (0°C) into steam (100°C) is as follows Heat required in the given process $ =Q _{1}+Q _{2}+Q _{3} $

$ =1\times 80+1\times 1\times (100-0)+1\times 536=716cal $



NCERT Chapter Video Solution

Dual Pane