SATHEE: Properties Of Solids And Liquids Question 237

Properties Of Solids And Liquids Question 237

Question: Water flows in a streamlined manner through a capillary tube of radius a, the pressure difference being P and the rate of flow Q. If the radius is reduced to a/2 and the pressure increased to 2P, the rate of flow becomes

Options:

A) 9.4 m

B) 4.9 m

C) 0.49 m

D) 0.94 m

Show Answer

Answer:

Correct Answer: D

Solution:

Given, $l_{1} = l_{2} = 1,$ and $\frac{r_{1}}{r_{2}} = \frac{1}{2}$

$V = \frac{π P_{1} r_{1}^{4}}{8 η l} = \frac{π P_{2} r_{2}^{4}}{8 η l}$

therefore $\frac{P_{1}}{P_{2}} = {(\frac{r_{2}}{r_{1}})}^{4} = 16$

therefore $P_{1} = 16 P_{2}$

Since both tubes are connectedin series, hence pressure difference across combination, $P = P_{1} + P_{2}$

therefore 1 = $P_{1} + \frac{P_{1}}{16}$

therefore $P_{1} = \frac{16}{17} = 0.94 m$

Properties Of Solids And Liquids Question 237

Question: Water flows in a streamlined manner through a capillary tube of radius a, the pressure difference being P and the rate of flow Q. If the radius is reduced to a/2 and the pressure increased to 2P, the rate of flow becomes

Options:

Answer:

Solution:

Engineering Preparation

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NCERT Books & Solutions

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Other Resources

Syllabus

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Sample Mock Test

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NCERT Exercise Video Solution

Properties Of Solids And Liquids Question 237

Question: Water flows in a streamlined manner through a capillary tube of radius a, the pressure difference being P and the rate of flow Q. If the radius is reduced to a/2 and the pressure increased to 2P, the rate of flow becomes

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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