Properties Of Solids And Liquids Question 227

Question: Water is flowing through a tube of non-uniform cross-section ratio of the radius at entry and exit end of the pipe is 3 : 2. Then the ratio of velocities at entry and exit of liquid is [RPMT 2001]

Options:

A) 4 : 9

B) 9 : 4

C) 8 : 27

D) 1 : 1

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Answer:

Correct Answer: A

Solution:

If velocities of water at entry and exit points are v1 and v2, then according to equation of continuity,

$ A _{1}v _{1}=A _{2}v _{2} $

therefore $ \frac{v _{1}}{v _{2}}=\frac{A _{2}}{A _{1}}={{\left( \frac{r _{2}}{r _{1}} \right)}^{2}}={{\left( \frac{2}{3} \right)}^{2}}=\frac{4}{9} $



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