Properties Of Solids And Liquids Question 21

Question: 540 g of ice at 0°C is mixed with 540 g of water at 80°C. The final temperature of the mixture is [AFMC 1994]

Options:

A) 0°C

B) 40°C

C) 80°C

D) Less than 0°C

Show Answer

Answer:

Correct Answer: A

Solution:

Heat taken by ice to melt at 0°C is Q1=mL=540×80=43200cal

Heat given by water to cool upto 0°C is Q2=msΔθ=540×1×(800)=43200cal

Hence heat given by water is just sufficient to melt the whole ice and final temperature of mixture is 0°C.

Short trick : For these type of frequently asked questions you can remember the following formula θmix=mWθWmiLicWmi+mW

(See theory for more details) If mW=mi

then θmix=θWLicW2=808012=0C



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