Properties Of Solids And Liquids Question 118

Question: 10 gm of ice at - 20°C is dropped into a calorimeter containing 10 gm of water at 10°C; the specific heat of water is twice that of ice. When equilibrium is reached, the calorimeter will contain

Options:

A) 20 gm of water

B) 20 gm of ice

C) 10 gm ice and 10 gm water

D) 5 gm ice and 15 gm water

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Answer:

Correct Answer: C

Solution:

Heat given by water $ Q _{1}=10\times 10=100cal. $

Heat taken by ice to melt Q2 = 10 ´ 0.5 ´ [0 - (- 20)] + 10 ´ 80 = 900 cal .

As $ Q _{1}<Q _{2}, $ so ice will not completely melt and final temperature = 0°C.

As heat given by water in cooling up to 0°C is only just sufficient to increase the temperature of ice from - 20°C to 0°C, hence mixture in equilibrium will consist of 10 gm ice and 10 gm water at 0°C.



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