Physics And Measurement Question 72
Question: The dimensions of coefficient of thermal conductivity is
[MP PMT 1993]
Options:
A) $ ML^{2}{{T}^{-2}}{{K}^{-1}} $
B) $ ML{{T}^{-3}}{{K}^{-1}} $
C) $ ML{{T}^{-2}}{{K}^{-1}} $
D) $ ML{{T}^{-3}}K $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{dQ}{dt}=-KA( \frac{d\theta }{dx} ) $
$ \Rightarrow $ [K] = $ \frac{[ML^{2}{{T}^{-2}}]}{[T]}\times \frac{[L]}{[L^{2}]\ [K]} $ = $ ML{{T}^{-3}}{{K}^{-1}} $
