Physics And Measurement Question 56

Question: The dimensional formula for Planck’s constant $ (h) $ is

[AFMC 2003; RPMT 1999; Kerala PMT 2002]

Options:

A) $ M{{L}^{-2}}{{T}^{-3}} $

B) $ ML^{2}{{T}^{-2}} $

C) $ ML^{2}{{T}^{-1}} $

D) $ M{{L}^{-2}}{{T}^{-2}} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ E=hv\Rightarrow [ML^{2}{{T}^{-2}}]=[h][{{T}^{-1}}]\Rightarrow [h]=[ML^{2}{{T}^{-1}}] $



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