Physics And Measurement Question 56
Question: The dimensional formula for Planck’s constant $ (h) $ is
[AFMC 2003; RPMT 1999; Kerala PMT 2002]
Options:
A) $ M{{L}^{-2}}{{T}^{-3}} $
B) $ ML^{2}{{T}^{-2}} $
C) $ ML^{2}{{T}^{-1}} $
D) $ M{{L}^{-2}}{{T}^{-2}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ E=hv\Rightarrow [ML^{2}{{T}^{-2}}]=[h][{{T}^{-1}}]\Rightarrow [h]=[ML^{2}{{T}^{-1}}] $
