SATHEE: Physics And Measurement Question 48

Physics And Measurement Question 48

Question: Dimensional formula for volume elasticity is

[MP PMT 1991, 2002; CPMT 1991; MNR 1986]

Options:

A) $M^{1} L^{- 2} T^{- 2}$

B) $M^{1} L^{- 3} T^{- 2}$

C) $M^{1} L^{2} T^{- 2}$

D) $M^{1} L^{- 1} T^{- 2}$

Show Answer

Answer:

Correct Answer: D

Solution:

Volume elasticity = $\frac{Force/Area}{Volume strain}$ Strain is dimensionless, so $\frac{F o r c e}{A r e a} = \frac{M L T^{- 2}}{L^{2}} = [M L^{- 1} T^{- 2}]$

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Physics And Measurement Question 48

Question: Dimensional formula for volume elasticity is

Options:

Answer:

Solution:

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