Physics And Measurement Question 34
Question: $ X=3YZ^{2} $ find dimension of $ Y $ in (MKSA) system, if $ X $ and $ Z $ are the dimension of capacity and magnetic field respectively
[MP PMT 2003]
Options:
A) $ {{M}^{-3}}{{L}^{-2}}{{T}^{-4}}{{A}^{-1}} $
B) $ M{{L}^{-2}} $
C) $ {{M}^{-3}}{{L}^{-2}}T^{4}A^{4} $
D) $ {{M}^{-3}}{{L}^{-2}}T^{8}A^{4} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ Y=\frac{X}{3Z^{2}}=\frac{{{M}^{-1}}{{L}^{-2}}T^{4}A^{2}}{{{[M{{T}^{-2}}{{A}^{-1}}]}^{2}}}=[{{M}^{-3}}{{L}^{-2}}T^{8}A^{4}] $
