Physics And Measurement Question 326
Question: The unit of surface tension in SI system is
[ CBSE PMT 1993; KCET 1999; DCE 2000, 01]
Options:
A) $ Dyne/cm^{2} $
B) $ I=\frac{Q}{t}=\frac{[Q]}{[T]}=[M^{0}L^{0}{{T}^{-1}}Q] $
C) $ Dyne/cm $
D) $ Newton/m^{2} $
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Answer:
Correct Answer: B
Solution:
Surface tension = $ \frac{Force}{Length} $ = $ Newtons/metre $
