Physics And Measurement Question 301

Options:

A) 5%

B) 4.5%

C) 8%

D) 7.75%

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Given: $ Q={{x}^{2/5}}{{y}^{-1}}{{t}^{-1/2}}z^{3} $
$ \therefore \frac{\Delta Q}{Q}\times 100 $

$ =\frac{2}{5}\frac{\Delta x}{x}\times 100+\frac{\Delta y}{y}\times 100 $

$ +\frac{1}{2}\frac{\Delta t}{t}\times 100+3\frac{\Delta z}{z}\times 100 $

$ =\frac{2}{5}\times 2.5+2+\frac{1}{2}\times 1+3\times 0.5=5% $



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