Physics And Measurement Question 250
Question: Write the dimensions of $ a\times b $ in the relation $ E=\frac{b-x^{2}}{at} $ where E is the energy, x is the displacement and t is time
Options:
A) $ ML^{2}T $
B) $ {{M}^{-1}}L^{2}T^{1} $
C) $ ML^{2}{{T}^{-2}} $
D) $ ML{{T}^{-2}} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Here, b and $ x^{2}=L^{2} $ have same dimensions Also, $ a=\frac{x^{2}}{E\times t}=\frac{L^{2}}{(ML^{2}{{T}^{-2}})T}={{M}^{-1}}T^{1} $
$ a\times b=[{{M}^{-1}}L^{2}T^{1}] $
