SATHEE: Physics And Measurement Question 178

Physics And Measurement Question 178

Question: The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 s, 2.56 s, 2.42 s, 2.71 s and 2.80 s respectively. The average absolute error is

Options:

A) 0.1 s

B) 0.11 s

C) 0.01 s

D) 1.0 s

Show Answer

Answer:

Correct Answer: B

Solution:

Average value $= \frac{2.63 + 2.56 + 2.42 + 2.71 + 2.80}{5}$

$= 2.62 \sec$ Now $| Δ T_{1} | = 2.63 - 2.62 = 0.01$

$| Δ T_{2} | = 2.62 - 2.56 = 0.06$

$| Δ T_{3} | = 2.62 - 2.42 = 0.20$

$| Δ T_{4} | = 2.71 - 2.62 = 0.09$

$| Δ T_{5} | = 2.80 - 2.62 = 0.18$ Mean absolute error $Δ T = \frac{| Δ T_{1} | + | Δ T_{2} | + | Δ T_{3} | + | Δ T_{4} | + | Δ T_{5} |}{5}$

$= \frac{0.54}{5} = 0.108 = 0.11 s e c$

Physics And Measurement Question 178

Question: The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 s, 2.56 s, 2.42 s, 2.71 s and 2.80 s respectively. The average absolute error is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Physics And Measurement Question 178

Question: The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 s, 2.56 s, 2.42 s, 2.71 s and 2.80 s respectively. The average absolute error is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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