Physics And Measurement Question 176

Question: The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is (5.00 $ \pm 0.05 $ ) Newton and weight in water is (4.00 $ \pm $ 0.05) Newton. Then the relative density along with the maximum permissible percentage error is

Options:

A) 5.0 $ \pm $ 11%

B) 5.0 $ \pm $ 1%

C) 5.0 $ \pm $ 6%

D) 1.25 $ \pm $ 5%

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Answer:

Correct Answer: A

Solution:

Weight in air $ =(5.00\pm 0.05)N $

Weight in water $ =(4.00\pm 0.05)N $

Loss of weight in water $ =(1.00\pm 0.1)N $

Now relative density $ =\frac{weightin\text{air }}{\text{weight }\text{loss in water}} $

i.e. R . D $ =\frac{5.00\pm 0.05}{1.00\pm 0.1} $

Now relative density with max permissible error $ =\frac{5.00}{1.00}\pm ( \frac{0.05}{5.00}+\frac{0.1}{1.00} )\times 100 $

$ =5.0\pm (1+10)% $

$ =5.0\pm 11% $



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