Physics And Measurement Question 159
Question: Position of a body with acceleration ‘a’ is given by $ x=Ka^{m}t^{n}, $ here t is time. Find dimension of m and n?
[Orissa JEE 2005]
Options:
A) $ m=1 $ , $ n=1 $
B) $ m=1,\ n=2 $
C) $ m=2,\ n=1 $
D) $ m=2,\ n=2 $
Show Answer
Answer:
Correct Answer: B
Solution:
As $ x=Ka^{m}\times t^{n} $
$ [ M^{0}LT^{0} ]={{[ L{{T}^{-2}} ]}^{m}}{{[ T ]}^{n}}=[ L^{m}{{T}^{-2m+n}} ] $
$ \therefore $ $ m=1 $ and $ -2m+n=0 $
therefore $ n=2 $ .
