Physics And Measurement Question 158

Question: In the relation $ y=a\cos (\omega t-kx) $ , the dimensional formula for k is?

[BHU 2004]

Options:

A) $ [M^{0}{{L}^{-1}}{{T}^{-1}}] $

B) $ [M^{0}L{{T}^{-1}}] $

C) $ [M^{0}{{L}^{-1}}T^{0}] $

D) $ [M^{0}LT] $

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Answer:

Correct Answer: C

Solution:

$ [Kx] $ = Dimension of $ \omega t= $ (dimensionless) hence $ K=\frac{1}{X}=\frac{1}{L}=[ {{L}^{-1}} ] $ \ $ [K]=[{{L}^{-1}}] $



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