Physics And Measurement Question 158
Question: In the relation $ y=a\cos (\omega t-kx) $ , the dimensional formula for k is?
[BHU 2004]
Options:
A) $ [M^{0}{{L}^{-1}}{{T}^{-1}}] $
B) $ [M^{0}L{{T}^{-1}}] $
C) $ [M^{0}{{L}^{-1}}T^{0}] $
D) $ [M^{0}LT] $
Show Answer
Answer:
Correct Answer: C
Solution:
$ [Kx] $ = Dimension of $ \omega t= $ (dimensionless) hence $ K=\frac{1}{X}=\frac{1}{L}=[ {{L}^{-1}} ] $ \ $ [K]=[{{L}^{-1}}] $
