Physics And Measurement Question 147
Question: The dimensions of $ K $ in the equation $ W=\frac{1}{2}Kx^{2} $ is?
[Orissa JEE 2003]
Options:
A) $ M^{1}L^{0}{{T}^{-2}} $
B) $ M^{0}L^{1}{{T}^{-1}} $
C) $ M^{1}L^{1}{{T}^{-2}} $
D) $ M^{1}L^{0}{{T}^{-1}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ W=\frac{1}{2}kx^{2}\Rightarrow [k]=\frac{[W]}{[x^{2}]}=[ \frac{ML^{2}{{T}^{-2}}}{L^{2}} ]=[M{{T}^{-2}}] $
