Physics And Measurement Question 128

Question: If pressure $ P $ , velocity $ V $ and time $ T $ are taken as fundamental physical quantities, the dimensional formula of force is

[EAMCET (Eng.) 2000]

Options:

A) $ PV^{2}T^{2} $

B) $ {{P}^{-1}}V^{2}{{T}^{-2}} $

C) $ PVT^{2} $

D) $ {{P}^{-1}}VT^{2} $

Show Answer

Answer:

Correct Answer: A

Solution:

Let $ F\propto P^{x}V^{y}T^{z} $

by substituting the following dimensions :

$ [P]=[M{{L}^{-1}}{{T}^{-2}}] $

$ [V]=[L{{T}^{-1}}],[T]=[T] $

and comparing the dimension of both sides $ x=1,y=2,z=2 $ , so $ F=PV^{2}T^{2} $



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