Physics And Measurement Question 128
Question: If pressure $ P $ , velocity $ V $ and time $ T $ are taken as fundamental physical quantities, the dimensional formula of force is
[EAMCET (Eng.) 2000]
Options:
A) $ PV^{2}T^{2} $
B) $ {{P}^{-1}}V^{2}{{T}^{-2}} $
C) $ PVT^{2} $
D) $ {{P}^{-1}}VT^{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
Let $ F\propto P^{x}V^{y}T^{z} $
by substituting the following dimensions :
$ [P]=[M{{L}^{-1}}{{T}^{-2}}] $
$ [V]=[L{{T}^{-1}}],[T]=[T] $
and comparing the dimension of both sides $ x=1,y=2,z=2 $ , so $ F=PV^{2}T^{2} $
