SATHEE: Physics And Measurement Question 111

Physics And Measurement Question 111

Question: The dimensions of permittivity $ε_{0}$ are

[MP PET 1997; AIIMS-2004; DCE-2003]

Options:

A) $A^{2} T^{2} M^{- 1} L^{- 3}$

B) $A^{2} T^{4} M^{- 1} L^{- 3}$

C) $A^{- 2} T^{- 4} M L^{3}$

D) $A^{2} T^{- 4} M^{- 1} L^{- 3}$

Show Answer

Answer:

Correct Answer: B

Solution:

$F = \frac{1}{4 π ε_{0}} \frac{q_{1} q_{2}}{r^{2}}$

$\Rightarrow$ $ε_{0} = \frac{| q_{1} | | q_{2} |}{[F] [r^{2}]} = \frac{[A^{2} T^{2}]}{[M L T^{- 2}] [L^{2}]} = [A^{2} T^{4} M^{- 1} L^{- 3}]$

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Physics And Measurement Question 111

Question: The dimensions of permittivity ε0 are

Options:

Answer:

Solution:

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Question: The dimensions of permittivity $ε_{0}$ are