Optics Question 984

Question: Glass has refractive index m with respect to air and the critical angle for a ray of light going from glass to air is q. If a ray of light is incident from air on the glass with angle of incidence q, the corresponding angle of refraction is

[MP PMT 2004]

Options:

A) $ {{\sin }^{-1}}( \frac{1}{\sqrt{\mu }} ) $

B) $ 90^{o} $

C) $ {{\sin }^{-1}}( \frac{1}{{{\mu }^{2}}} ) $

D) $ {{\sin }^{-1}}( \frac{1}{\mu } ) $

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Answer:

Correct Answer: C

Solution:

$ _{a}{\mu _{g}}=\frac{1}{\sin \theta } $

$ \Rightarrow \mu =\frac{1}{\sin \theta } $ …..(i) Now from Snell’s law $ \mu =\frac{\sin i}{\sin r} $

$ =\frac{\sin \theta }{\sin r} $

$ \Rightarrow \sin r=\frac{\sin \theta }{\mu } $ …..(ii) From equation (i) and (ii) $ \sin r=\frac{1}{{{\mu }^{2}}} $

$ \Rightarrow r={{\sin }^{-1}}( \frac{1}{{{\mu }^{2}}} ) $



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