SATHEE: Optics Question 97

Optics Question 97

Question: A ray of light is incident on the hypotenuse of a right-angled prism after travelling parallel to the base inside the prism. If m is the refractive index of the material of the prism, the maximum value of the base angle for which light is totally reflected from the hypotenuse is

[EAMCET 2003]

Options:

A) $\sin^{- 1} (\frac{1}{μ})$

B) $\tan^{- 1} (\frac{1}{μ})$

C) $\sin^{- 1} (\frac{μ - 1}{μ})$

D) $\cos^{- 1} (\frac{1}{μ})$

Show Answer

Answer:

Correct Answer: D

Solution:

If $α$ = maximum value of base angle for which light is totally reflected form hypotenuse. $(90^{\circ} - α)$ = C = minimum value of angle of incidence at hypotenuse for total internal reflection $\sin (90^{\circ} - α) = \sin C = \frac{1}{μ}$

$\Rightarrow \cos α = \frac{1}{μ}$

$\Rightarrow α = \cos^{- 1} (\frac{1}{μ})$

Optics Question 97

Question: A ray of light is incident on the hypotenuse of a right-angled prism after travelling parallel to the base inside the prism. If m is the refractive index of the material of the prism, the maximum value of the base angle for which light is totally reflected from the hypotenuse is

Options:

Answer:

Solution:

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Optics Question 97

Question: A ray of light is incident on the hypotenuse of a right-angled prism after travelling parallel to the base inside the prism. If m is the refractive index of the material of the prism, the maximum value of the base angle for which light is totally reflected from the hypotenuse is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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