SATHEE: Optics Question 966

Optics Question 966

Question: A ray of light is incident at an angle i from denser to rare medium. The reflected and the refracted rays are mutually perpendicular. The angle of reflection and the angle of refraction are respectively r and r’ , then the critical angle will be

[IIT-JEE 1983; MP PET 1995; CBSE PMT 1996; MP PMT 1985, 99; Pb. PET 2002]

Options:

A) $\sin^{- 1} (\sin r)$

B) $\sin^{- 1} (\tan r^{'})$

C) $\sin^{- 1} (\tan i)$

D) $\tan^{- 1} (\sin i)$

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Answer:

Correct Answer: C

Solution:

$_{D} μ_{R} = \frac{\sin i}{\sin r^{'}} \Rightarrow_{R} μ_{D} = \frac{\sin r^{'}}{\sin i} = \frac{1}{\sin C}$

$\Rightarrow \sin C = \frac{\sin i}{\sin (90 - r)} = \frac{\sin i}{\cos r} = \frac{\sin i}{\cos i}$ (as Ði = Ðr)

$\Rightarrow \sin C = \tan i \Rightarrow C = \sin^{- 1} (\tan i)$

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Optics Question 966

Question: A ray of light is incident at an angle i from denser to rare medium. The reflected and the refracted rays are mutually perpendicular. The angle of reflection and the angle of refraction are respectively r and r’ , then the critical angle will be

Options:

Answer:

Solution:

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