SATHEE: Optics Question 96

Optics Question 96

Question: The refracting angle of prism is A and refractive index of material of prism is $\cot \frac{A}{2}$ . The angle of minimum deviation is

[CPMT 1992]

Options:

A) 180°? 3A

B) 180° + 2A

C) 90° ?A

D) 180° ? 2A

Show Answer

Answer:

Correct Answer: D

Solution:

By using $μ = \frac{\sin \frac{A + δ_{m}}{2}}{\sin \frac{A}{2}}$

$\Rightarrow$ $\cot \frac{A}{2} = \frac{\sin \frac{A + δ_{m}}{2}}{\sin \frac{A}{2}}$

$\Rightarrow \frac{\cos \frac{A}{2}}{\sin \frac{A}{2}} = \frac{\sin \frac{A + δ_{m}}{2}}{\sin \frac{A}{2}}$

$\Rightarrow$ $\sin (90^{\circ} - \frac{A}{2}) = \sin (\frac{A + δ_{m}}{2})$

$\Rightarrow δ_{m} = 180 - 2 A$

Optics Question 96

Question: The refracting angle of prism is A and refractive index of material of prism is $\cot \frac{A}{2}$ . The angle of minimum deviation is

Options:

Answer:

Solution:

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Optics Question 96

Question: The refracting angle of prism is A and refractive index of material of prism is cot⁡A2 . The angle of minimum deviation is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The refracting angle of prism is A and refractive index of material of prism is $\cot \frac{A}{2}$ . The angle of minimum deviation is