SATHEE: Optics Question 958

Optics Question 958

Question: If the signal is transmitted from an optical fibre core of Refractive Index (RI) $\sqrt{\frac{12}{5}}$ to an another optical fibre with RI of core and cladding as 1.8 and 1.2 respectively, then the maximum angle of acceptance for 2nd optical fibre is

Options:

A) $30^{\circ}$

B) $45^{\circ}$

C) $60^{\circ}$

D) $\sin^{- 1} (\frac{2}{\sqrt{3}})$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Idea In optical fibre maximum angle of accepts is given by

$\sin θ = \frac{\sqrt{n_{1}^{2} - n_{2}^{2}}}{n_{0}}$

Maximum angle of acceptance is given by

$\sin θ = \frac{\sqrt{n_{1}^{2} - n_{2}^{2}}}{n_{0}} = \frac{\sqrt{{1.8}^{2} - {1.2}^{2}}}{\sqrt{12 / 5}}$

$= \sqrt{(1.8 - 1.2) (1.8 + 1.2)} \times \sqrt{\frac{5}{12}}$

$\Rightarrow$ $\sin θ = \sqrt{0.6 \times 3} \times \sqrt{\frac{5}{12}} = \frac{\sqrt{3}}{2}$

$\Rightarrow$ $θ = \sin^{- 1} (\frac{\sqrt{3}}{2})$

$\Rightarrow$ $θ = 60^{\circ}$

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Optics Question 958

Question: If the signal is transmitted from an optical fibre core of Refractive Index (RI) 125 to an another optical fibre with RI of core and cladding as 1.8 and 1.2 respectively, then the maximum angle of acceptance for 2nd optical fibre is

Options:

Answer:

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Question: If the signal is transmitted from an optical fibre core of Refractive Index (RI) $\sqrt{\frac{12}{5}}$ to an another optical fibre with RI of core and cladding as 1.8 and 1.2 respectively, then the maximum angle of acceptance for 2nd optical fibre is